2[t-(4t+16)+10]=2(t+6)

Solution for 2[t-(4t+16)+10]=2(t+6) equation:

Simplifying
2[t + -1(4t + 16) + 10] = 2(t + 6)

Reorder the terms:
2[t + -1(16 + 4t) + 10] = 2(t + 6)
2[t + (16 * -1 + 4t * -1) + 10] = 2(t + 6)
2[t + (-16 + -4t) + 10] = 2(t + 6)

Reorder the terms:
2[-16 + 10 + t + -4t] = 2(t + 6)

Combine like terms: -16 + 10 = -6
2[-6 + t + -4t] = 2(t + 6)

Combine like terms: t + -4t = -3t
2[-6 + -3t] = 2(t + 6)
[-6 * 2 + -3t * 2] = 2(t + 6)
[-12 + -6t] = 2(t + 6)

Reorder the terms:
-12 + -6t = 2(6 + t)
-12 + -6t = (6 * 2 + t * 2)
-12 + -6t = (12 + 2t)

Solving
-12 + -6t = 12 + 2t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2t' to each side of the equation.
-12 + -6t + -2t = 12 + 2t + -2t

Combine like terms: -6t + -2t = -8t
-12 + -8t = 12 + 2t + -2t

Combine like terms: 2t + -2t = 0
-12 + -8t = 12 + 0
-12 + -8t = 12

Add '12' to each side of the equation.
-12 + 12 + -8t = 12 + 12

Combine like terms: -12 + 12 = 0
0 + -8t = 12 + 12
-8t = 12 + 12

Combine like terms: 12 + 12 = 24
-8t = 24

Divide each side by '-8'.
t = -3

Simplifying
t = -3